Optimal. Leaf size=255 \[ \frac{32 b^3 (a+b x)^{5/2} (-13 a B e+8 A b e+5 b B d)}{15015 e (d+e x)^{5/2} (b d-a e)^5}+\frac{16 b^2 (a+b x)^{5/2} (-13 a B e+8 A b e+5 b B d)}{3003 e (d+e x)^{7/2} (b d-a e)^4}+\frac{4 b (a+b x)^{5/2} (-13 a B e+8 A b e+5 b B d)}{429 e (d+e x)^{9/2} (b d-a e)^3}+\frac{2 (a+b x)^{5/2} (-13 a B e+8 A b e+5 b B d)}{143 e (d+e x)^{11/2} (b d-a e)^2}-\frac{2 (a+b x)^{5/2} (B d-A e)}{13 e (d+e x)^{13/2} (b d-a e)} \]
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Rubi [A] time = 0.163884, antiderivative size = 255, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125, Rules used = {78, 45, 37} \[ \frac{32 b^3 (a+b x)^{5/2} (-13 a B e+8 A b e+5 b B d)}{15015 e (d+e x)^{5/2} (b d-a e)^5}+\frac{16 b^2 (a+b x)^{5/2} (-13 a B e+8 A b e+5 b B d)}{3003 e (d+e x)^{7/2} (b d-a e)^4}+\frac{4 b (a+b x)^{5/2} (-13 a B e+8 A b e+5 b B d)}{429 e (d+e x)^{9/2} (b d-a e)^3}+\frac{2 (a+b x)^{5/2} (-13 a B e+8 A b e+5 b B d)}{143 e (d+e x)^{11/2} (b d-a e)^2}-\frac{2 (a+b x)^{5/2} (B d-A e)}{13 e (d+e x)^{13/2} (b d-a e)} \]
Antiderivative was successfully verified.
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Rule 78
Rule 45
Rule 37
Rubi steps
\begin{align*} \int \frac{(a+b x)^{3/2} (A+B x)}{(d+e x)^{15/2}} \, dx &=-\frac{2 (B d-A e) (a+b x)^{5/2}}{13 e (b d-a e) (d+e x)^{13/2}}+\frac{(5 b B d+8 A b e-13 a B e) \int \frac{(a+b x)^{3/2}}{(d+e x)^{13/2}} \, dx}{13 e (b d-a e)}\\ &=-\frac{2 (B d-A e) (a+b x)^{5/2}}{13 e (b d-a e) (d+e x)^{13/2}}+\frac{2 (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{143 e (b d-a e)^2 (d+e x)^{11/2}}+\frac{(6 b (5 b B d+8 A b e-13 a B e)) \int \frac{(a+b x)^{3/2}}{(d+e x)^{11/2}} \, dx}{143 e (b d-a e)^2}\\ &=-\frac{2 (B d-A e) (a+b x)^{5/2}}{13 e (b d-a e) (d+e x)^{13/2}}+\frac{2 (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{143 e (b d-a e)^2 (d+e x)^{11/2}}+\frac{4 b (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{429 e (b d-a e)^3 (d+e x)^{9/2}}+\frac{\left (8 b^2 (5 b B d+8 A b e-13 a B e)\right ) \int \frac{(a+b x)^{3/2}}{(d+e x)^{9/2}} \, dx}{429 e (b d-a e)^3}\\ &=-\frac{2 (B d-A e) (a+b x)^{5/2}}{13 e (b d-a e) (d+e x)^{13/2}}+\frac{2 (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{143 e (b d-a e)^2 (d+e x)^{11/2}}+\frac{4 b (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{429 e (b d-a e)^3 (d+e x)^{9/2}}+\frac{16 b^2 (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{3003 e (b d-a e)^4 (d+e x)^{7/2}}+\frac{\left (16 b^3 (5 b B d+8 A b e-13 a B e)\right ) \int \frac{(a+b x)^{3/2}}{(d+e x)^{7/2}} \, dx}{3003 e (b d-a e)^4}\\ &=-\frac{2 (B d-A e) (a+b x)^{5/2}}{13 e (b d-a e) (d+e x)^{13/2}}+\frac{2 (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{143 e (b d-a e)^2 (d+e x)^{11/2}}+\frac{4 b (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{429 e (b d-a e)^3 (d+e x)^{9/2}}+\frac{16 b^2 (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{3003 e (b d-a e)^4 (d+e x)^{7/2}}+\frac{32 b^3 (5 b B d+8 A b e-13 a B e) (a+b x)^{5/2}}{15015 e (b d-a e)^5 (d+e x)^{5/2}}\\ \end{align*}
Mathematica [A] time = 0.380652, size = 135, normalized size = 0.53 \[ \frac{2 (a+b x)^{5/2} \left (1155 (B d-A e)-\frac{(d+e x) \left (2 b (d+e x) \left (4 b (d+e x) (-5 a e+7 b d+2 b e x)+35 (b d-a e)^2\right )+105 (b d-a e)^3\right ) (-13 a B e+8 A b e+5 b B d)}{(b d-a e)^4}\right )}{15015 e (d+e x)^{13/2} (a e-b d)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.01, size = 505, normalized size = 2. \begin{align*} -{\frac{256\,A{b}^{4}{e}^{4}{x}^{4}-416\,Ba{b}^{3}{e}^{4}{x}^{4}+160\,B{b}^{4}d{e}^{3}{x}^{4}-640\,Aa{b}^{3}{e}^{4}{x}^{3}+1664\,A{b}^{4}d{e}^{3}{x}^{3}+1040\,B{a}^{2}{b}^{2}{e}^{4}{x}^{3}-3104\,Ba{b}^{3}d{e}^{3}{x}^{3}+1040\,B{b}^{4}{d}^{2}{e}^{2}{x}^{3}+1120\,A{a}^{2}{b}^{2}{e}^{4}{x}^{2}-4160\,Aa{b}^{3}d{e}^{3}{x}^{2}+4576\,A{b}^{4}{d}^{2}{e}^{2}{x}^{2}-1820\,B{a}^{3}b{e}^{4}{x}^{2}+7460\,B{a}^{2}{b}^{2}d{e}^{3}{x}^{2}-10036\,Ba{b}^{3}{d}^{2}{e}^{2}{x}^{2}+2860\,B{b}^{4}{d}^{3}e{x}^{2}-1680\,A{a}^{3}b{e}^{4}x+7280\,A{a}^{2}{b}^{2}d{e}^{3}x-11440\,Aa{b}^{3}{d}^{2}{e}^{2}x+6864\,A{b}^{4}{d}^{3}ex+2730\,B{a}^{4}{e}^{4}x-12880\,B{a}^{3}bd{e}^{3}x+23140\,B{a}^{2}{b}^{2}{d}^{2}{e}^{2}x-18304\,Ba{b}^{3}{d}^{3}ex+4290\,B{b}^{4}{d}^{4}x+2310\,A{a}^{4}{e}^{4}-10920\,A{a}^{3}bd{e}^{3}+20020\,A{a}^{2}{b}^{2}{d}^{2}{e}^{2}-17160\,Aa{b}^{3}{d}^{3}e+6006\,A{b}^{4}{d}^{4}+420\,B{a}^{4}d{e}^{3}-1820\,B{a}^{3}b{d}^{2}{e}^{2}+2860\,B{a}^{2}{b}^{2}{d}^{3}e-1716\,Ba{b}^{3}{d}^{4}}{15015\,{a}^{5}{e}^{5}-75075\,{a}^{4}bd{e}^{4}+150150\,{a}^{3}{b}^{2}{d}^{2}{e}^{3}-150150\,{a}^{2}{b}^{3}{d}^{3}{e}^{2}+75075\,a{b}^{4}{d}^{4}e-15015\,{b}^{5}{d}^{5}} \left ( bx+a \right ) ^{{\frac{5}{2}}} \left ( ex+d \right ) ^{-{\frac{13}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 4.01254, size = 1567, normalized size = 6.15 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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